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Question Number 192639 by pascal889 last updated on 24/May/23

$$$$lim_(x⇒∝ ) ((3x^3 +3x^2 +1)/(5x^3 +4x^2 +x)) find the limit

Answered by Subhi last updated on 24/May/23

$$\frac{3}{5}$$$$$$

Commented by pascal889 last updated on 24/May/23

$$\mathrm{ple}ase\mathrm{sir}\mathrm{i}\mathrm{need}\mathrm{the}\mathrm{working}\mathrm{so}\mathrm{i}\mathrm{can}\mathrm{tap}\mathrm{from}\mathrm{you}\mathrm{sirplease}\mathrm{sir}$$

Answered by cortano12 last updated on 24/May/23

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{{\mathrm{x}}^3(3+\frac{3}{\mathrm{x}}+\frac{1}{{\mathrm{x}}^3})}{{\mathrm{x}}^3(5+\frac{4}{\mathrm{x}}+\frac{1}{{\mathrm{x}}^2})}=$$$$\underset{x\to \mathrm{\infty }}{\lim }\left(\frac{3+\frac{3}{\mathrm{x}}+\frac{1}{{\mathrm{x}}^3}}{5+\frac{4}{\mathrm{x}}+\frac{1}{{\mathrm{x}}^2}}\right)=\frac{3+0}{5+0}=\frac{3}{5}$$

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