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Question Number 192648 by pascal889 last updated on 24/May/23

$$\mathbf{find}\mathbf{g}\left(\mathbf{f}\left(\mathbf{x}\right)\right)$$$$\mathbf{f}\left(\mathbf{x}\right)={\mathbf{x}}^3-{\mathbf{x}}^2+3\mathbf{x}$$$$\mathbf{g}\left(\mathbf{x}\right)={\mathbf{x}}^2-2\mathbf{x}+1$$

Answered by Skabetix last updated on 24/May/23

$$g\left(f\left(x\right)\right)={(x^3-x^2+3x)}^2-2(x^3-x^2+3x)+1=x^6-2x^5+7x^4-8x^3+11x^2-6x+1$$

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