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Question Number 192648 by pascal889 last updated on 24/May/23
findg(f(x))f(x)=x3−x2+3xg(x)=x2−2x+1
Answered by Skabetix last updated on 24/May/23
g(f(x))=(x3−x2+3x)2−2(x3−x2+3x)+1=x6−2x5+7x4−8x3+11x2−6x+1
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