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Question Number 192651 by beto last updated on 24/May/23
limx→02−cos(x)−cos(x)x2
Answered by cortano12 last updated on 24/May/23
L=limx→0(1−cosx)+(1−cosx)x2L=limx→01−cosx2x2+limx→01−cosxx2L=limx→03(1−cosx)2x2L=limx→03.sin2x4x2=34
Answered by Subhi last updated on 24/May/23
limx→012+1−cos(x)x2.1+cos(x)1+cos(x)12+1−cos(x)x2.(1+cos(x))12+2sin2(x2)x2(1+cos(x))limx→0(12+12.(1+cos(x)))=12+14=34
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