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Question Number 192661 by Mingma last updated on 24/May/23

Commented by Mingma last updated on 24/May/23

Prove that

Commented by Mingma last updated on 25/May/23

Perfect ��

Answered by deleteduser1 last updated on 24/May/23

(√1)+(√2)+...+(√(2n−1))≤(2n−1)(√(((2n−1)(2n))/(2(2n−1))))=(2n−1)(√n) ⇒(1/( (√n)))((√1)+(√2)+...+(√(2n−1)))≤2n−1

1+2+...+2n−1⩽(2n−1)(2n−1)(2n)2(2n−1)=(2n−1)n⇒1n(1+2+...+2n−1)⩽2n−1

Commented by Mingma last updated on 25/May/23

Perfect ��

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