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Question Number 192687 by Mastermind last updated on 24/May/23
1π∫02πxcos(nx)dxHelp!
Answered by Subhi last updated on 24/May/23
x=u⇛du=dxcos(nx)dx=dvv=1n∫n.cos(nx)=1n.sin(nx)∫u.dv=u.v−∫v.du=x.sin(nx)n−1n∫sin(nx).dxx.sin(nx)n+1n2∫−n.sin(nx).dxx.sin(nx)n+1n2.cos(nx)+c1π∫x.cos(nx)dx=x.sin(nx)nπ+1n2.πcos(nx)+c
Commented by Subhi last updated on 24/May/23
tofindthedefiniteintegral,itwilldifferif(n)isintegerorfraction
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