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Question Number 192704 by Mingma last updated on 25/May/23

Answered by HeferH last updated on 25/May/23

Commented by HeferH last updated on 25/May/23

$$12+12\sqrt{3}-x=24$$$$x=12(\sqrt{3}-1)$$$$shaded=\frac{12(\sqrt{3}-1)\cdot 6}{2}=36(\sqrt{3}-1)u^2$$

Commented by Mingma last updated on 25/May/23

Perfect ��

Answered by MM42 last updated on 25/May/23

$$BC=24sin15\mathrm{\&}<BCD={105}^0$$$$△BCD:\frac{12}{sin105}=\frac{24sin15}{sinD}$$$$\Rightarrow sinD=2sin105sin15=2cos15sin15=\frac{1}{2}\Rightarrow <D={30}^0\Rightarrow <CBD={45}^0$$$$\Rightarrow S_{BCD}=\frac{1}{2}\times 12\times 24\times sin15\times sin45=36(\sqrt{3}-1)✓$$

Commented by MM42 last updated on 25/May/23

Commented by Mingma last updated on 25/May/23

Perfect ��

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