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Question Number 192733 by Mingma last updated on 25/May/23

Answered by MM42 last updated on 25/May/23

((1−((2tanA)/(1+tan^2 A)))/(1+((1−tan^2 A)/(1+tan^2 A))))=tanA−1 ((tan^2 A−2tanA+1)/2)=tanA−1 tan^2 A−4tanA+3=0 tanA=1 × or tanA=3 ✓ ⇒tan^2 A= 9

1−2tanA1+tan2A1+1−tan2A1+tan2A=tanA−1tan2A−2tanA+12=tanA−1tan2A−4tanA+3=0tanA=1×ortanA=3✓⇒tan2A=9

Commented by Mingma last updated on 25/May/23

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