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Question Number 192803 by mokys last updated on 27/May/23

Commented by mokys last updated on 28/May/23

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Answered by MM42 last updated on 29/May/23

Q1:  3+2t+6t−t=−4⇒t=−1⇒p(1,−2,−1)  u_L ^→ =n_P ^→ =(1,3,−1)⇒L′: x=t+1  &  y=3t−2  &  z=−t−1  Q2:  AB(2,0,−1) ,  AC(2,−1,0)  N^→ =AB^→ ×AC^→ =(1,2,2)⇒P : x+2y+2z=0  ⇒PH=((∣1+8∣)/( (√(1+4+4))))=1 ✓  Q3:  it is not clear

Q1:3+2t+6tt=4t=1p(1,2,1)uL=nP=(1,3,1)L:x=t+1&y=3t2&z=t1Q2:AB(2,0,1),AC(2,1,0)N=AB×AC=(1,2,2)P:x+2y+2z=0PH=1+81+4+4=1Q3:itisnotclear

Commented by MM42 last updated on 29/May/23

Commented by MM42 last updated on 29/May/23

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