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Question Number 192858 by josemate19 last updated on 29/May/23

$${\int }_{4x}^{x^3}\sqrt{\sqrt{t}+t^{1/3}}dt$$

Answered by Frix last updated on 29/May/23

$$\int \sqrt{\sqrt{t}+\sqrt[3]{t}}dt=$$$$=\frac{4\sqrt{1+\sqrt[6]{t}}}{15015}(3003t^{\frac{7}{6}}+231t-252t^{\frac{5}{6}}+280t^{\frac{2}{3}}-320t^{\frac{1}{2}}+384t^{\frac{1}{3}}-512t^{\frac{1}{6}}+1024)+C$$$$\mathrm{Now}\mathrm{do}\mathrm{me}\mathrm{a}\mathrm{favour}\mathrm{and}\mathrm{insert}\mathrm{the}\mathrm{borders}$$$$\mathrm{for}\mathrm{yourself}!$$

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