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Question Number 192959 by Mingma last updated on 31/May/23

Answered by a.lgnaoui last updated on 01/Jun/23

$$△\mathrm{MYX}\mathrm{et}\mathrm{KYX}\mathrm{triangles}\mathrm{rectangles}$$$$\mathrm{en}\mathrm{plus}\mathrm{la}\mathrm{corde}\mathrm{commun}\mathrm{YZ}=2\mathrm{XY}$$$$\Rightarrow \mathrm{YX}=\frac{\mathrm{YZ}}{2}=10$$$$\mathrm{MK}=\mathrm{MX}+\mathrm{XK}$$$$△\mathrm{MYX}{\mathrm{MY}}^2={\mathrm{MX}}^2+{\mathrm{XY}}^2$$$$\mathrm{MX}=\sqrt{{22}^2-{10}^2}=19,60$$$$△\mathrm{KXY}{\mathrm{YK}}^2={\mathrm{KX}}^2+{\mathrm{XY}}^2$$$$\mathrm{KX}=\sqrt{{18}^2-{10}^2}=\sqrt{384}=15$$$$\mathrm{alors}\mathbf{MK}=\mathbf{MX}+\mathbf{XK}=34,6$$$$$$

Commented by Mingma last updated on 01/Jun/23

Good ��

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