Question Number 19301 by saa last updated on 09/Aug/17
$${e}^{{i}\pi} +\mathrm{1}=\mathrm{0} \\ $$
Answered by ajfour last updated on 09/Aug/17
$$\mathrm{e}^{\mathrm{i}\pi} =−\mathrm{1}\:. \\ $$
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Question Number 19301 by saa last updated on 09/Aug/17 | ||
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$${e}^{{i}\pi} +\mathrm{1}=\mathrm{0} \\ $$ | ||
Answered by ajfour last updated on 09/Aug/17 | ||
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$$\mathrm{e}^{\mathrm{i}\pi} =−\mathrm{1}\:. \\ $$ | ||