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Question Number 193073 by Tawa11 last updated on 03/Jun/23

Answered by Subhi last updated on 03/Jun/23

$$$$$$thesystemisinequalibrium$$$$\mathrm{\Sigma }f=0atx,yaxis$$$$p.cos\left(30\right)+2.sin\left(45\right)-Q.sin\left(60\right)=0$$$$\frac{\sqrt{3}}{2}.p-\frac{\sqrt{3}}{2}Q=-\sqrt{2}$$$$P-Q=\frac{-2\sqrt{6}}{3}\left(i\right)$$$$p.sin\left(30\right)+2.cos\left(45\right)+5-8+Q.cos\left(60\right)=0$$$$\frac{p}{2}+\frac{Q}{2}=3-\sqrt{2}$$$$P+Q=6-2\sqrt{2}\left(ii\right)$$$$P=\frac{6-2\sqrt{2}-\frac{2\sqrt{6}}{3}}{2}=0.769N$$$$Q=2.4N$$

Commented by Tawa11 last updated on 04/Jun/23

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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