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Question Number 193111 by cortano12 last updated on 04/Jun/23

$$\downharpoonleft \underset{―}{}$$

Answered by math1234 last updated on 04/Jun/23

Answered by horsebrand11 last updated on 04/Jun/23

$$\Rightarrow 2=\frac{3}{2}{\mathrm{a}}^2+\frac{1}{2}\mathrm{a};\mathrm{a}⩾0$$$$\Rightarrow {3\mathrm{a}}^2+\mathrm{a}-4=0$$$$\Rightarrow (3\mathrm{a}+4)(\mathrm{a}-1)=0$$$$\Rightarrow \mathrm{a}=1$$

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