Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 193116 by Mastermind last updated on 04/Jun/23

Show that for all a,b,c,d ∈ R with  a,b,c,d ≥ 0   1) (√(ab))(√(cd)) ≤ (1/4)(a^2 +b^2 +c^2 +d^2 )  2) (abcd)^(1/4)  ≤ (1/4)(a+b+c+d)    Help!

Showthatforalla,b,c,dRwitha,b,c,d01)abcd14(a2+b2+c2+d2)2)(abcd)1414(a+b+c+d)Help!

Answered by Subhi last updated on 04/Jun/23

1) 4(a^2 +b^2 +c^2 +d^2 )≥(a+b+c+d)^2   a+b+c+d≥4^4 (√(abcd))      (AM - GM)  (a+b+c+d)^2 ≥16(√(abcd))  4(a^2 +b^2 +c^2 +d^2 )≥16(√(abcd))  (1/4)(a^2 +b^2 +c^2 +d^2 )≥(√(ab)).(√(cd))

1)4(a2+b2+c2+d2)(a+b+c+d)2a+b+c+d44abcd(AMGM)(a+b+c+d)216abcd4(a2+b2+c2+d2)16abcd14(a2+b2+c2+d2)ab.cd

Commented by Subhi last updated on 04/Jun/23

4(a^2 +b^2 +c^2 +d^2 )≥(a+b+c+d)^2   (a+b+c+d)^2 =a^2 +b^2 +c^2 +d^2 +2cd+2ab+2ac+2ad+2bc+2bd  = a^2 +b^2 +c^2 +d^2 +2(ab+ac+ad+bc+bd+cd)   (i)  a^2 +b^2 +c^2 +d^2   a^2 +b^2 ≥2(√(a^2 .b^2 ))=2ab     (AM−GM)  b^2 +c^2 ≥2bc          ⇛  c^2 +d^2 ≥2cd  a^2 +d^2 ≥2ad        ⇛  b^2 +d^2 ≥2bd  a^2 +c^2 ≥2ac  sum the 5 equations  3(a^2 +b^2 +c^2 +d^2 )≥2(ab+bc+ac+ad+bd+cd)   (ii)  from (i) , (ii)  (a+b+c+d)^2 ≤4(a^2 +b^2 +c^2 +d^2 )

4(a2+b2+c2+d2)(a+b+c+d)2(a+b+c+d)2=a2+b2+c2+d2+2cd+2ab+2ac+2ad+2bc+2bd=a2+b2+c2+d2+2(ab+ac+ad+bc+bd+cd)(i)a2+b2+c2+d2a2+b22a2.b2=2ab(AMGM)b2+c22bcc2+d22cda2+d22adb2+d22bda2+c22acsumthe5equations3(a2+b2+c2+d2)2(ab+bc+ac+ad+bd+cd)(ii)from(i),(ii)(a+b+c+d)24(a2+b2+c2+d2)

Commented by Mastermind last updated on 04/Jun/23

Thank you so much

Thankyousomuch

Commented by Mastermind last updated on 04/Jun/23

Thank you my boss

Thankyoumyboss

Commented by Mastermind last updated on 04/Jun/23

What′s AM−GM?

WhatsAMGM?

Commented by Subhi last updated on 04/Jun/23

Arithmetic geometric mean inequality  its proof is below ↓

Arithmeticgeometricmeaninequalityitsproofisbelow

Answered by Subhi last updated on 04/Jun/23

proof for AM − GM  ((√a)−(√b))^2 ≥0  a+b−2(√(ab)) ≥0  ((a+b)/2)≥(√(ab))  ((a_1 +a_2 +.........a_n )/n)≥^n (√(a_1 .a_2 ......a_n ))  ((a+b+c+d)/4)≥^4 (√(abcd))

proofforAMGM(ab)20a+b2ab0a+b2aba1+a2+.........annna1.a2......ana+b+c+d44abcd

Terms of Service

Privacy Policy

Contact: info@tinkutara.com