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Question Number 193230 by MATHEMATICSAM last updated on 07/Jun/23

Choose the correct option:  If a, b and c are consecutive positive  integers and log(1 + ac) = 2k then the  value of k is:  a) log a  b) log b  c) 2  d) 1  Give the explaination also.

Choosethecorrectoption:Ifa,bandcareconsecutivepositiveintegersandlog(1+ac)=2kthenthevalueofkis:a)logab)logbc)2d)1Givetheexplainationalso.

Answered by Rajpurohith last updated on 08/Jun/23

let a=b−1 ; c=b+1 (since a ,b and c are consecutive.)  so 1+ac=1+(b−1)(b+1)=1+b^2 −1=b^2   ⇒log(1+ac)=log(b^2 )=2log(b)=2k  hence k=log(b).

leta=b1;c=b+1(sincea,bandcareconsecutive.)so1+ac=1+(b1)(b+1)=1+b21=b2log(1+ac)=log(b2)=2log(b)=2khencek=log(b).

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