s=a+b+c+d+..... number terms :n {a;b;c;d.....}>0 then E=s/(s−a)+s/(s−b)+s/s−c)+.... a) E>=n^2 b)E>=n^2 /(n−1) c) E>=n/(n+1) d) E>=n^2 /(n+1) e) E>=n^2 −1


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Question Number 193238 by lmcp1203 last updated on 08/Jun/23
$s=a+b+c+d+..... number terms :n {a;b;c;d.....}>0 then E=s/(s−a)+s/(s−b)+s/s−c)+.... a) E>=n^2 b)E>=n^2 /(n−1) c) E>=n/(n+1) d) E>=n^2 /(n+1) e) E>=n^2 −1$
$s = a + b + c + d + . . . . .$ $n u m b e r t e r m s : n$ ${a; b; c; d . . . . .} > 0$ $t h e n E = s / (s - a) + s / (s - b) + s / s - c) + . . . .$ $a) E >= n^{2} b) E >= n^{2} / (n - 1)$ $c) E >= n / (n + 1) d) E >= n^{2} / (n + 1)$ $e) E >= n^{2} - 1$
	Answered by MM42 last updated on 08/Jun/23

	$E ⩾ n \sqrt[n]{\frac{s^{n}}{(s - a) (s - b) (s - c) . . .}} = \frac{n s}{\sqrt[n]{(s - a) (s - b) (s - c) . . .}}$ $⩾ \frac{n^{2} s}{(s - a) + (s - b) + (s - c) + . . .} = \frac{n^{2} s}{n s - s} = \frac{n^{2}}{n - 1} ✓ (b)$
	Commented by lmcp1203 last updated on 08/Jun/23

	$t h a n k y o u$
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