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Question Number 193345 by yaslm last updated on 11/Jun/23

	Answered by aleks041103 last updated on 13/Jun/23

	$T h e t r a j e c t r y o f t h e w a t e r i s a f r e e f a l l p a r a b o l l a$ $\Rightarrow H = \frac{1}{2} {g t}^{2} \Rightarrow t = \sqrt{\frac{2 H}{g}}$ $D = v t = v \sqrt{\frac{2 H}{g}}$ $\Rightarrow v = \sqrt{\frac{{g D}^{2}}{2 H}}$ $t h e n t h e f l o w r a t e Φ i s$ $Φ = v S = \frac{1}{4} π d^{2} v$ $\Rightarrow Φ = \frac{π d^{2} D}{4} \sqrt{\frac{g}{2 H}}$
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