Question and Answers Forum

All Questions      Topic List

Arithmetic Questions

Previous in All Question      Next in All Question      

Previous in Arithmetic      Next in Arithmetic      

Question Number 193449 by Mingma last updated on 14/Jun/23

Commented by Frix last updated on 14/Jun/23

The remainder of 10^n −1 divided by 625  is 624 for n≥4

Theremainderof10n1dividedby625is624forn4

Commented by Mingma last updated on 14/Jun/23

Can you explain in details?

Commented by Frix last updated on 14/Jun/23

n≥4:  10^n −1=10^n −625+624=  =10^(n−4) ×10000−625+624=  =10^(n−4) ×16×625−625+624=  =(10^(n−4) ×16−1)×625+624  ⇔  ((10^n −1)/(625))=10^(n−4) ×16−1+((624)/(625))

n4:10n1=10n625+624==10n4×10000625+624==10n4×16×625625+624==(10n4×161)×625+62410n1625=10n4×161+624625

Commented by Mingma last updated on 14/Jun/23

Perfect ��

Answered by MM42 last updated on 14/Jun/23

625=5^4   N=10^(100) −1=2^(100) ×(5^4 )^(25) −1 ≡^(625)  −1≡^(625)  624 ✓

625=54N=101001=2100×(54)2516251625624

Commented by Mingma last updated on 14/Jun/23

Perfect ��

Terms of Service

Privacy Policy

Contact: info@tinkutara.com