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Question Number 193461 by SAMIRA last updated on 14/Jun/23
limx→0(1+sinx−1sin2x)=??
Answered by aba last updated on 14/Jun/23
=limx→01+sinx−1sin(2x)(1+sinx+1)=limx→012cosx(1+sinx+1)=14✓
Answered by MM42 last updated on 14/Jun/23
limx→0(sinxsin2x(1+sinx+1))=14
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