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Question Number 193492 by Socracious last updated on 15/Jun/23

Answered by a.lgnaoui last updated on 15/Jun/23

$$\mathrm{DE}\mid \mid \mathrm{BC}$$$$\tan 30=\frac{\sqrt{3}}{3}=\frac{\mathbf{HB}}{\mathbf{HA}}=\frac{\mathbf{b}}{2\mathbf{x}}\Rightarrow \mathbf{x}=\frac{\mathbf{b}\sqrt{3}}{2}$$$$\mathbf{S}=\mathbf{x}.\frac{\mathbf{b}}{2}=\frac{{\mathbf{b}}^2}{4}\sqrt{3}\mathbf{Area}=\frac{{\mathrm{b}}^2\sqrt{3}}{4}$$$$$$

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