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Question Number 193554 by Mingma last updated on 16/Jun/23

Answered by aba last updated on 17/Jun/23

$$\mathrm{a}=1\wedge \mathrm{b}=0$$

Answered by aba last updated on 17/Jun/23

$${\left(\begin{array}{c}10\\ 01\end{array}\right)}^{\mathrm{k}}=\left(\begin{array}{c}{1}^{\mathrm{k}}0\\ 01^{\mathrm{k}}\end{array}\right)=\left(\begin{array}{c}10\\ 01\end{array}\right)$$$${\left(\begin{array}{c}\mathrm{a}\mathrm{b}\\ -\mathrm{b}1\end{array}\right)}^6={\left(\begin{array}{c}10\\ 01\end{array}\right)}^6\Rightarrow \left(\begin{array}{c}\mathrm{a}\mathrm{b}\\ -\mathrm{b}1\end{array}\right)=\left(\begin{array}{c}10\\ 01\end{array}\right)$$$$\Rightarrow \{\begin{array}{l}\mathrm{a}=1✓\\ \mathrm{b}=0✓\end{array}$$

Commented by Rupesh123 last updated on 17/Jun/23

Perfect ��

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