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Question Number 193687 by Mingma last updated on 18/Jun/23

Commented by Frix last updated on 18/Jun/23

$$\mathrm{Squaring}\mathrm{\&}\mathrm{transforming}3\mathrm{times}\mathrm{leads}\mathrm{to}$$$$x^8-\frac{10x^7}{3}+\frac{143x^6}{27}-\frac{854x^5}{81}+\frac{4352x^4}{243}-\frac{4678x^3}{243}+\frac{611x^2}{27}-\frac{1922x}{81}+\frac{817}{81}=0$$$$x=3^{\frac{1}{3}}\mathrm{is}\mathrm{a}\mathrm{solution}$$$$\mathrm{I}\mathrm{found}\mathrm{this}\mathrm{factorization}:$$$$(x^3-3)(x^5-\frac{10x^4}{3}+\frac{143x^3}{27}-\frac{611x^2}{81}+\frac{1922x}{243}-\frac{817}{243})=0$$

Commented by Mingma last updated on 18/Jun/23

Perfect ��

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