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Question Number 193688 by Mingma last updated on 18/Jun/23

Answered by cortano12 last updated on 18/Jun/23

 4(2p+1)^2 −4.(−1).(−2p−31)<0   4p^2 +4p+1−2p−31<0   4p^2 +2p−30<0   2p^2 +p−15<0   (2p −5)(p+3)<0   −3<p<(5/2)   the largest positive integer p is 2

4(2p+1)24.(1).(2p31)<04p2+4p+12p31<04p2+2p30<02p2+p15<0(2p5)(p+3)<03<p<52thelargestpositiveintegerpis2

Commented by Mingma last updated on 18/Jun/23

Perfect ��

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