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Question Number 193835 by Skabetix last updated on 20/Jun/23

Commented by a.lgnaoui last updated on 21/Jun/23

$$\mathrm{respecter}\mathrm{les}\mathrm{mesures}\mathrm{pour}\mathrm{avoir}\mathrm{une}$$$$\mathrm{idee}\mathrm{de}\mathrm{la}\mathrm{question}$$$$Jecroisquecestlapremuerefoisque$$$$tuenvoieunequestionauforum.$$$$\mathrm{l}\mathrm{inconu}\mathrm{dans}\mathrm{votre}\mathrm{question}\mathrm{est}\mathbf{DE}$$$$\mathbf{AB}\mathrm{doit}-\mathrm{etre}:18\mathrm{non}\mathrm{pas}75(\mathrm{d}\mathrm{apres}$$$$\mathrm{les}\mathrm{le}\mathrm{dessin}(\mathrm{AD}=75\mathrm{AB}=18)$$$$$$$$\mathrm{question}\mathrm{doit}\mathrm{etre}$$$$$$$$\mathrm{AB}=18\mathrm{AC}=4$$$$\mathrm{AD}=75\mathrm{AD}=14$$$$\mathrm{DE}=85\mathrm{BC}?$$

Answered by Skabetix last updated on 20/Jun/23

$$DE=?$$$$WecannotuseThalestheorembecauseof$$$$\left(BC\right)\nparallel \left(DE\right)$$

Answered by Subhi last updated on 21/Jun/23

$${(8.5)}^2={(7.5)}^2+4^2$$$$\therefore B\widehat{AC}=90$$$$DE=\sqrt{{\left(AD\right)}^2+{\left(AE\right)}^2}=\sqrt{{(25.5)}^2+{\left(14\right)}^2}=29.1$$

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