If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?


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Question Number 193883 by byaw last updated on 22/Jun/23

If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?
	Answered by Subhi last updated on 22/Jun/23

	$m a s s f l o w r a t e = \frac{m}{t} = \frac{9000}{60} = 150 k g / s$ $\frac{m}{t} = ρ A v = 1000 \times 0.3 v = 300 v = 150$ $v = \frac{150}{300} = \frac{1}{2} m / s$
	Commented by York12 last updated on 22/Jun/23

	$s i r h o w c a n I r e a c h y o u o u t$
	Commented by byaw last updated on 22/Jun/23

	$please how did you get the 1000 in 1000 \times 0.3 v ?$ $ρ A v stands for ?$ $v is velocity ?$ $A is cross - section area ?$ $ρ is pressure ?$
	Commented by Subhi last updated on 22/Jun/23

	$ρ i s t h e d e n i s i t y$ $\frac{m}{t} = \frac{ρ v}{t} = \frac{d e n i s i t y \times l e n g t h \times a r e a}{t i m e} = d e n i s i t y \times a r e a \times v e l o c i t y = ρ A v$
	Commented by Subhi last updated on 22/Jun/23

	$I t h i n k y o u h a v e d i s c o r d$ $You can't use 'macro parameter character #' in math mode$ $s e n d m e$ $\underset{―}{\underset{⏟}{N}}$
	Commented by byaw last updated on 23/Jun/23

	A(-1, 2), B(3, 5) and C(4, 8) are the vertices of triangle ABC. Forces whose magnitudes are 5N and 3√10N act along (AB) ⃗ and (CB) ⃗ respectively. Find the direction of the resultant of the forces. please help.
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