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Question Number 193962 by Abdullahrussell last updated on 24/Jun/23

Answered by deleteduser1 last updated on 24/Jun/23

$$\Rightarrow f\left(x\right)=Q\left(x\right)(x-a)(x-b)+R\Rightarrow f\left(a\right)=R,f\left(b\right)=R$$$$\Rightarrow \frac{f\left(a\right)(x-b)-f\left(b\right)(x-a)}{a-b}=\frac{R(x-b-x+a)}{a-b}=R$$

Answered by cortano12 last updated on 24/Jun/23

$$\underbrace{}$$

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