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Question Number 194073 by Rupesh123 last updated on 27/Jun/23

Answered by BaliramKumar last updated on 27/Jun/23

$$10\pi$$

Answered by mr W last updated on 27/Jun/23

$$methodI:$$$$\sqrt{R^2-4^2}+\sqrt{R^2-2^2}=6$$$$\sqrt{R^2-4}=4$$$$\Rightarrow R^2=20$$$$semicircle=\frac{\pi R^2}{2}=10\pi$$

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