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Question Number 194089 by a.lgnaoui last updated on 27/Jun/23

$$\mathrm{Determiner}\mathrm{le}\mathrm{rayon}\mathbf{r}$$

Commented by a.lgnaoui last updated on 27/Jun/23

Commented by cherokeesay last updated on 27/Jun/23

Commented by a.lgnaoui last updated on 28/Jun/23

$$\mathrm{thanks}$$

Answered by mr W last updated on 27/Jun/23

$$90°+\alpha =135°$$$$\Rightarrow \alpha =45°$$$${\left(\sqrt{2}r\right)}^2={(12+2)}^2+2^2$$$$\Rightarrow r=10$$

Commented by mr W last updated on 27/Jun/23

Commented by a.lgnaoui last updated on 28/Jun/23

$$\mathrm{thanks}$$

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