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Question Number 194113 by Rupesh123 last updated on 28/Jun/23

Answered by Subhi last updated on 28/Jun/23

((a(a−1)(a−2).....)/(a(a−2)(a−4).....)).((b(b−2)(b−4)...)/(b(b−1)(b−2)....)) = (((a−1)(a−3)(a−5).....)/((b−1)(b−3)(b−5).....)) 24 can be the multiplication of n, n+2 (4),(6) a−1 = 6 , a−3 = 4 ⇛ a = 7 a−5 = 2 = (b−1) ⇛ b = 3 a + b = 10

a(a−1)(a−2).....a(a−2)(a−4)......b(b−2)(b−4)...b(b−1)(b−2)....=(a−1)(a−3)(a−5).....(b−1)(b−3)(b−5).....24canbethemultiplicationofn,n+2(4),(6)a−1=6,a−3=4⇛a=7a−5=2=(b−1)⇛b=3a+b=10

Commented by Rupesh123 last updated on 28/Jun/23

Perfect ��

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