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Question Number 194127 by Rupesh123 last updated on 28/Jun/23

Answered by MM42 last updated on 28/Jun/23

$$AC=CE\Rightarrow <CAE=45\Rightarrow BH=AH$$$$\frac{BH}{8}=\frac{HF}{6}\Rightarrow 3BH=4(6-BH)$$$$\Rightarrow BH=\frac{24}{7}\Rightarrow S=\frac{72}{7}$$$$$$

Answered by cortano12 last updated on 28/Jun/23

$$\Rightarrow \mathrm{t}+\frac{3}{4}\mathrm{t}=6;\mathrm{t}=\overline{)\begin{array}{c}\frac{24}{7}\end{array}}$$$$\Rightarrow \mathrm{blue}\mathrm{area}=\frac{1}{2}\times 6\times \frac{24}{7}=\overline{)\begin{array}{c}\frac{72}{7}\end{array}}$$

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