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Question Number 194147 by DAVONG last updated on 28/Jun/23

$$\underset{\mathrm{n}\to +\mathrm{\infty }}{\lim }(\frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{{\mathrm{n}}^2})=?$$

Answered by Frix last updated on 28/Jun/23

$$\frac{{\pi }^2}{6}$$

Answered by 123564 last updated on 03/Jul/23

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