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Question Number 194219 by Shlock last updated on 30/Jun/23

Answered by Frix last updated on 30/Jun/23

(x^3 +4x−8)(x^3 −2x^2 +8)(x+2)= =x^7 +64x^2 −128 x^3 +4x−8=0 ⇒ x^7 +64x^2 −128=0 ⇔ x^7 +64x^2 =128

(x3+4x−8)(x3−2x2+8)(x+2)==x7+64x2−128x3+4x−8=0⇒x7+64x2−128=0⇔x7+64x2=128

Commented by Shlock last updated on 30/Jun/23

Thanks, sir!

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