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Question Number 194240 by cherokeesay last updated on 01/Jul/23

Answered by BaliramKumar last updated on 01/Jul/23

$$28✓$$

Answered by a.lgnaoui last updated on 01/Jul/23

$$\mathrm{t}=\frac{3}{14}\Rightarrow \cos \alpha =\frac{1}{\sqrt{1+{\mathrm{t}}^2}}=\frac{14\sqrt{205}}{205}$$$$\mathrm{BI}=\mathrm{BFcos}\alpha \sin \alpha =\frac{3\sqrt{205}}{205}$$$$\sin \alpha =\frac{3}{2\mathrm{BF}}\mathrm{BF}=\frac{3}{2\sin \alpha }=\frac{\sqrt{205}}{2}$$$$\Rightarrow \mathrm{BI}=\frac{\sqrt{205}}{2}\times \frac{14\sqrt{205}}{205}=7$$$$\mathrm{dinc}\mathrm{MI}=11-\mathrm{BI}=4$$$$\mathrm{Area}=\frac{\mathbf{ME}\times \mathbf{MI}}{2}=\frac{14\times 4}{2}$$$$\mathbf{Area}\left(\mathbf{MEF}\right)=28$$

Commented by a.lgnaoui last updated on 01/Jul/23

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