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Question Number 194256 by horsebrand11 last updated on 01/Jul/23

$$\underset{x\to 0}{\lim }\frac{\frac{1+\tan \mathrm{x}}{1-\tan \mathrm{x}}-1}{\mathrm{x}}=?$$

Answered by tri26112004 last updated on 01/Jul/23

$$=\underset{x\to 0}{\lim }\frac{2tanx}{x(1-tanx)}$$$$=\underset{x\to 0}{\lim }\frac{tanx}{x}.\underset{x\to 0}{\lim }\frac{2}{1-tanx}$$$$=1.\frac{2}{1-0}=2$$

Answered by cortano12 last updated on 01/Jul/23

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