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Question Number 194297 by York12 last updated on 02/Jul/23

Let a , b , c be  real positive numbers &   abc=1   prove that  ((ab)/(a^5 +b^5 +ab))+((bc)/(b^5 +c^5 +bc))+((ac)/(a^5 +c^5 +ac))≤1

Leta,b,cberealpositivenumbers&abc=1provethataba5+b5+ab+bcb5+c5+bc+aca5+c5+ac1

Answered by deleteduser1 last updated on 02/Jul/23

a^5 +b^5 +ab≥a^3 b^2 +b^3 a^2 +ab=a^2 b^2 (a+b)+ab  ⇒Σ((ab)/(a^5 +b^5 +ab))≤Σ(1/(ab(a+b+c)))=Σ(c/(a+b+c))=1

a5+b5+aba3b2+b3a2+ab=a2b2(a+b)+abΣaba5+b5+abΣ1ab(a+b+c)=Σca+b+c=1

Commented by York12 last updated on 02/Jul/23

sir what is the motivation to use the first inequality

sirwhatisthemotivationtousethefirstinequality

Commented by deleteduser1 last updated on 02/Jul/23

Rearrangement inequality  Let {a_i },{b_i }_(1≤i≤n)  be increasing sequences or both  decreasing.  Then Σ_(i=1) ^n a_i b_i ≥a_1 b_i_p  +a_2 b_i_p_2   +....+a_n b_i_p_n     where i_p_j   is the jth term in any permution of {n}

RearrangementinequalityLet{ai},{bi}1inbeincreasingsequencesorbothdecreasing.Thenni=1aibia1bip+a2bip2+....+anbipnwhereipjisthejthterminanypermutionof{n}

Commented by York12 last updated on 02/Jul/23

Thanks so much sir , I really appreciate  it

Thankssomuchsir,Ireallyappreciateit

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