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Question Number 194315 by cortano12 last updated on 03/Jul/23

Answered by Frix last updated on 03/Jul/23

$$\mathrm{This}\mathrm{can}\mathrm{be}\mathrm{transformed}\mathrm{to}[s=\sin x]:$$$$s^4+\frac{s^3}{2}-s^2-\frac{s}{2}+\frac{1}{16}=0$$$$\mathrm{which}\mathrm{can}\mathrm{be}\mathrm{solved}\mathrm{the}\mathrm{usual}\mathrm{way}.$$

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