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Question Number 194331 by 073 last updated on 03/Jul/23

Answered by Frix last updated on 03/Jul/23

cos x =C A+B=1 ⇔ B=1−A S_n =C^4 A^n +(C^2 −1)^2 (1−A)^n = =(A^n +(1−A)^n )C^4 −2(1−A)^n C^2 +(1−A)^n It′s easy to show ((S_6 −S_5 )/(4S_4 ))=((S_(10) −S_9 )/(4S_8 ))=((A(A−1))/4) ⇒ Answer is ((A^2 −A)/2) We know A^2 −A−4=0 ⇔ A^2 −A=4 ⇒ Answer is 2

cosx=CA+B=1⇔B=1−ASn=C4An+(C2−1)2(1−A)n==(An+(1−A)n)C4−2(1−A)nC2+(1−A)nIt′seasytoshowS6−S54S4=S10−S94S8=A(A−1)4⇒AnswerisA2−A2WeknowA2−A−4=0⇔A2−A=4⇒Answeris2

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