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Question Number 194386 by SANOGO last updated on 05/Jul/23
calculthethederiveofcos3(θ3)′
Answered by Frix last updated on 05/Jul/23
f(t)=t3g(t)=costh(t)=t3(f(g(h(t))))′=h′(t)×g′(h(t))×f′(g(h(t)))Weget13×(−sinθ3)×3cos2θ3=−sinθ3cos2θ3
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