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Question Number 194434 by SANOGO last updated on 06/Jul/23

$$calcul$$$$e^{2ln(1+u)}-e^{-2ln(1+u)}=?$$

Answered by aba last updated on 06/Jul/23

$${\mathrm{e}}^{2\ln (1+\mathrm{u})}-{\mathrm{e}}^{-2\ln (1+\mathrm{u})}={\mathrm{e}}^{\ln {(1+\mathrm{u})}^2}-{\mathrm{e}}^{\ln {\left(\frac{1}{1+\mathrm{u}}\right)}^2}$$$$={(1+\mathrm{u})}^2-\frac{1}{{(1+\mathrm{u})}^2}$$

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