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Question Number 194491 by horsebrand11 last updated on 08/Jul/23

$$\mathrm{x}=\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}$$$$\overline{)\begin{array}{c}2\mathrm{x}-1=?\end{array}}$$

Answered by cortano12 last updated on 08/Jul/23

$$\mathrm{x}=\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}$$$$\mathrm{x}=\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10(2+\sqrt{3})}}}$$$$\mathrm{x}=\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{28-10\sqrt{3}}}}$$$$\mathrm{x}=\sqrt{4+\sqrt{5\sqrt{3}+5(5-\sqrt{3})}}$$$$\mathrm{x}=\sqrt{4+\sqrt{25}}=3$$$$\overline{)\begin{array}{c}2\mathrm{x}-1=5\end{array}}$$

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