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Question Number 194528 by BaliramKumar last updated on 09/Jul/23

★ Let N be a natural number where N≤100.          If HCF(N, 100) = 1 then find the sum of           all the values of  N ?         (a) 400       (b) 1000        (c) 2000        (d) 4000

LetNbeanaturalnumberwhereN100.IfHCF(N,100)=1thenfindthesumofallthevaluesofN?(a)400(b)1000(c)2000(d)4000

Answered by mahdipoor last updated on 09/Jul/23

(1+2+3+...+100)−(2+4+6+...100)  −(5+10+15+...+100)+(10+20+30+...+100)  =((100×101)/2)−((50×102)/2)−((20×105)/2)+((10×110)/2)  =2000

(1+2+3+...+100)(2+4+6+...100)(5+10+15+...+100)+(10+20+30+...+100)=100×101250×102220×1052+10×1102=2000

Commented by BaliramKumar last updated on 09/Jul/23

typo sir 4000→2000  Nice solution

typosir40002000Nicesolution

Commented by mahdipoor last updated on 09/Jul/23

you are right , i forget (/2) !

youareright,iforget2!

Answered by BaliramKumar last updated on 09/Jul/23

Apply Euler′s  totient function  Sum = 100×((𝛗(100))/2) = 100×((40)/2) = 100×20 = 2000

ApplyEulerstotientfunctionSum=100×ϕ(100)2=100×402=100×20=2000

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