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Question Number 194619 by Shrinava last updated on 11/Jul/23

$$\mathrm{Find}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{the}\mathrm{roots}\mathrm{of}\mathrm{the}$$$$\mathrm{equation}:$$$$-{3\mathrm{x}}^3+{8\mathrm{x}}^2-6\mathrm{x}-7=0$$

Answered by Frix last updated on 11/Jul/23

$$x^3-\frac{8}{3}{x}^2+2x+\frac{7}{3}=0$$$$(x-x_1)(x-x_2)(x-x_3)=0$$$$x^3-(x_1+x_2+x_3)x^2+(x_1{x}_2+x_1{x}_3+x_2{x}_3)x-x_1{x}_2{x}_3=0$$$$\mathrm{\Sigma }{x}_j=\frac{8}{3}$$

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