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Question Number 194662 by SANOGO last updated on 12/Jul/23

∫_0 ^(Π/2) (√(4sin^2 t+cos^2 t))  dt

0Π24sin2t+cos2tdt

Commented by Frix last updated on 12/Jul/23

Same as before:  4sin^2  t +cos^2  t =1+3sin^2  t

Sameasbefore:4sin2t+cos2t=1+3sin2t

Commented by SANOGO last updated on 12/Jul/23

ok thank you

okthankyou

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