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Question Number 194766 by dimentri last updated on 15/Jul/23

   1+2cot 2x cot x = 3      x=?

1+2cot2xcotx=3x=?

Answered by Frix last updated on 15/Jul/23

1+2cor 2x cot x =3  cot^2  x =3  cot x =±(√3)  x=±(π/6)+nπ; n∈Z

1+2cor2xcotx=3cot2x=3cotx=±3x=±π6+nπ;nZ

Commented by dimentri last updated on 15/Jul/23

Answered by MM42 last updated on 15/Jul/23

tan2x×tanx−3tan2xtanx+2=0  let   tanx=u  ((2u^2 )/(1−u^2 ))−((6u^2 )/(1−u^2 ))+2=0  ⇒u=tanx=±((√3)/3) ⇒x=kπ±(π/6) ✓

tan2x×tanx3tan2xtanx+2=0lettanx=u2u21u26u21u2+2=0u=tanx=±33x=kπ±π6

Commented by dimentri last updated on 15/Jul/23

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