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Question Number 194812 by sonukgindia last updated on 16/Jul/23

Answered by MM42 last updated on 16/Jul/23

$$A={lim}_{x\to 0}\frac{\frac{\sqrt{1-x^2}}{1-x}-(1+x)}{\frac{sinx-x}{x}}$$$$A={lim}_{x\to 0}\frac{x\sqrt{1-x^2}(1-\sqrt{1-x^2})}{(1-x)(sinx-x)}$$$$={lim}_{x\to 0}\frac{x\sqrt{1-x^2}\times x^2}{(1-x)\times (1+\sqrt{1-x^2})\times -\frac{1}{6}{x}^3}$$$$=-\frac{3}{2}✓$$

Answered by cortano12 last updated on 18/Jul/23

$$\text{Extra left or missing right}$$

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