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Question Number 194826 by cortano12 last updated on 16/Jul/23
tan19°=ptan7°=?
Answered by dimentri last updated on 16/Jul/23
tan38°=tan(45°−7)2tan19°1−tan219°=1−tan7°1+tan7°−tan7°+1tan7°+1=2p1−p2(p2−1)tan7°+1−p2=2ptan7°+2p(p2−2p−1)tan7°=p2+2p−1tan7°=p2+2p−1p2−2p−1
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