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Question Number 194826 by cortano12 last updated on 16/Jul/23

      tan 19° = p         tan 7° =?

tan19°=ptan7°=?

Answered by dimentri last updated on 16/Jul/23

   tan 38° = tan (45°−7)     ((2tan 19°)/(1−tan^2  19°)) = ((1−tan 7°)/(1+tan 7°))     ((−tan 7°+1)/(tan 7°+1)) = ((2p)/(1−p^2 ))     (p^2 −1) tan 7°+1−p^2 =2p tan 7°+2p    (p^2 −2p−1)tan 7°=p^2 +2p−1      determinant (((tan 7°=((p^2 +2p−1)/(p^2 −2p−1)))))

tan38°=tan(45°7)2tan19°1tan219°=1tan7°1+tan7°tan7°+1tan7°+1=2p1p2(p21)tan7°+1p2=2ptan7°+2p(p22p1)tan7°=p2+2p1tan7°=p2+2p1p22p1

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