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Question Number 194861 by cherokeesay last updated on 17/Jul/23

Answered by horsebrand11 last updated on 17/Jul/23

$$\mathrm{let}\mathrm{the}\mathrm{side}\mathrm{length}\mathrm{of}\mathrm{the}\mathrm{small}$$$$\mathrm{square}\mathrm{be}\mathrm{p}.$$$${(1+\mathrm{p})}^2+{\mathrm{p}}^2={\left(\sqrt{2}\right)}^2$$$${2\mathrm{p}}^2+2\mathrm{p}-1=0$$$$\mathrm{p}=\frac{\sqrt{3}-1}{2}$$$$\cancel{\underset{―}{\underbrace{}}}$$

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