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Question Number 194896 by cortano12 last updated on 19/Jul/23

Answered by deleteduser1 last updated on 19/Jul/23

$${(x^2-f\left(x\right))}^2+2x^{2}f\left(x\right)=1+2x^{2}f\left(x\right)$$$$\Rightarrow x^2-f\left(x\right)=\underset{-}{+}1\Rightarrow f\left(x\right)=x^2\stackrel{-}{+}1$$$$f\left(0\right)=1\Rightarrow f\left(x\right)=x^2+1$$

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