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Question Number 194915 by York12 last updated on 19/Jul/23

  (3/(x−3))+(5/(x−5))+(7/(x−17))+((19)/(x−19))=x^2 −11x−4

3x3+5x5+7x17+19x19=x211x4

Commented by BaliramKumar last updated on 19/Jul/23

typo   7→17

typo717

Commented by York12 last updated on 19/Jul/23

no sir , I am sure

nosir,Iamsure

Commented by BaliramKumar last updated on 19/Jul/23

i guess just

iguessjust

Commented by justenspi last updated on 19/Jul/23

8sybe it is a typo in my book

8sybeitisatypoinmybook

Answered by Rasheed.Sindhi last updated on 19/Jul/23

(3/(x−3))+(5/(x−5))+((17)/(x−17))+((19)/(x−19))=x^2 −11x−4  (3/(x−3))+1+(5/(x−5))+1+((17)/(x−17))+1+((19)/(x−19))+1=x^2 −11x  (x/(x−3))+(x/(x−5))+(x/(x−17))+(x/(x−19))−x^2 +11x=0  x((1/(x−3))+(1/(x−5))+(1/(x−17))+(1/(x−19))−x+11)=0   { ((x=0 ✓)),(((1/(x−3))+(1/(x−19))+(1/(x−5))+(1/(x−17))−x+11=0)) :}  ((2x−22)/(x^2 −22x+57))+((2x−22)/(x^2 −22x+85))−(x−11)=0  ((2(x−11))/(x^2 −22x+57))+((2(x−11))/(x^2 −22x+85))−(x−11)=0  (x−11)((2/(x^2 −22x+57))+(2/(x^2 −22x+85))−1)=0   { ((x−11=0⇒x=11✓)),(((2/(x^2 −22x+57))+(2/(x^2 −22x+85))−1=0)) :}  (2/(x^2 −22x+57))+(2/(x^2 −22x+85))=1  Let x^2 −22x=y  (2/(y+57))+(2/(y+85))=1  2y+170+2y+114=y^2 +142y+4845  y^2 +138y+4561=0     y=−69±10(√2)   x^2 −22x=−69±10(√2)      ......  ...........

3x3+5x5+17x17+19x19=x211x43x3+1+5x5+1+17x17+1+19x19+1=x211xxx3+xx5+xx17+xx19x2+11x=0x(1x3+1x5+1x17+1x19x+11)=0{x=01x3+1x19+1x5+1x17x+11=02x22x222x+57+2x22x222x+85(x11)=02(x11)x222x+57+2(x11)x222x+85(x11)=0(x11)(2x222x+57+2x222x+851)=0{x11=0x=112x222x+57+2x222x+851=02x222x+57+2x222x+85=1Letx222x=y2y+57+2y+85=12y+170+2y+114=y2+142y+4845y2+138y+4561=0y=69±102x222x=69±102.................

Commented by York12 last updated on 19/Jul/23

tbanks

tbanks

Commented by BaliramKumar last updated on 19/Jul/23

Nice approach

Niceapproach

Commented by Rasheed.Sindhi last updated on 20/Jul/23

🙏

🙏

Answered by Rasheed.Sindhi last updated on 20/Jul/23

(3/(x−3))+((19)/(x−19))+(5/(x−5))+((17)/(x−17))=x^2 −11x−4  ((3x−57+19x−57)/(x^2 −22x+57))+((5x−85+17x−85)/(x^2 −22x+85))=x^2 −11x−4  ((22x−114)/(x^2 −22x+57))+2+((22x−170)/(x^2 −22x+85))+2=x^2 −11x  ((2x^2 −22x)/(x^2 −22x+57))+((2x^2 −22x)/(x^2 −22x+85))−(x−11)x=0  x(x−11)((2/(x^2 −22x+57))+(2/(x^2 −22x+85))−1)=0  x=0,x=11, (2/(x^2 −22x+57))+(2/(x^2 −22x+85))−1=0  Let x^2 −22x=y  (2/(y+57))+(2/(y+85))=1  2y+170+2y+114=y^2 +142y+4845  y^2 +138y+4561=0  y=−69±10(√2)  x^2 −22x=−69±10(√2)

3x3+19x19+5x5+17x17=x211x43x57+19x57x222x+57+5x85+17x85x222x+85=x211x422x114x222x+57+2+22x170x222x+85+2=x211x2x222xx222x+57+2x222xx222x+85(x11)x=0x(x11)(2x222x+57+2x222x+851)=0x=0,x=11,2x222x+57+2x222x+851=0Letx222x=y2y+57+2y+85=12y+170+2y+114=y2+142y+4845y2+138y+4561=0y=69±102x222x=69±102

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