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Question Number 194952 by pascal889 last updated on 20/Jul/23

$$\mathbf{x}+\sqrt{17-{\mathbf{x}}^2}+\mathbf{x}\sqrt{17-{\mathbf{x}}^2}=9$$$$\mathbf{find}\mathbf{the}\mathbf{possible}\mathbf{value}\mathbf{of}\mathbf{X}$$

Answered by Frix last updated on 20/Jul/23

$$\mathrm{Obviously}x=1\vee x=4$$$$1+4+1\times 4=9$$$$4+1+4\times 1=9$$

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